Lesson 10 of 13 · 6 min
Colour in coordination compounds
NCERT §5.5.5; §5.5.6
The bottles on Farhan's shelf are violet, blue, yellow and green. Crystal field theory can tell him why each has its colour and why his dried copper sulphate turned white.
The lesson in notes
In short
A coloured complex absorbs part of the visible light passing through it; its colour is the complementary colour of what is left. If green is absorbed, the complex looks red.
Absorbed wavelength and colour seen: [CoCl(NH₃)₅]²⁺ 535 nm (yellow) looks violet; [Co(NH₃)₅(H₂O)]³⁺ 500 nm (blue-green) looks red; [Co(NH₃)₆]³⁺ 475 nm (blue) looks yellow-orange.
More pairs: [Co(CN)₆]³⁻ absorbs at 310 nm in the ultraviolet and is pale yellow; [Cu(H₂O)₄]²⁺ absorbs 600 nm (red) and looks blue; [Ti(H₂O)₆]³⁺ absorbs 498 nm (blue-green) and looks violet.
[Ti(H₂O)₆]³⁺ is d¹: the lone electron sits in t₂g. Blue-green light promotes it to eg (t₂g¹eg⁰ → t₂g⁰eg¹), so the complex looks violet. CFT puts colour down to such d-d transitions.
No ligand, no splitting, no colour: heating [Ti(H₂O)₆]Cl₃ to drive off water leaves a colourless solid, and anhydrous CuSO₄ is white while CuSO₄·5H₂O is blue.
Changing the ligand changes the colour. Adding en to green [Ni(H₂O)₆]²⁺ in en:Ni ratios 1:1, 2:1 and 3:1 gives pale blue [Ni(H₂O)₄(en)]²⁺, blue/purple [Ni(H₂O)₂(en)₂]²⁺ and violet [Ni(en)₃]²⁺.
Ruby is Al₂O₃ with about 0.5-1% Cr³⁺ (d³) in some Al³⁺ sites; these act like octahedral Cr(III) complexes whose d-d transitions give the colour. In emerald, Cr³⁺ sits in octahedral sites of beryl (Be₃Al₂Si₆O₁₈); its bands move to longer wavelengths (yellow-red and blue), so green is transmitted.
Limits of CFT: treating ligands as point charges predicts that anions should split most, yet anionic ligands sit at the weak end of the spectrochemical series; and CFT ignores the covalent side of metal-ligand bonding. Ligand field and molecular orbital theories handle these.